2012-11-13 18 views
5

Altıgen rengini RGB rengine dönüştürmek istiyorum. Altıgen renk dizesini RGB rengine dönüştürün

ben aşağıdaki kodu kullandı:

Me.BackColor = RGB("#000000") 

Ama sonra aşağıdaki istisna atar:

Argument not specified for parameter 'Green' of 'Public Function RGB(Red As Integer, Green As Integer, Blue As Integer) As Integer' 

bunu yapmak için doğru yolu nedir? ColorTranslator By

cevap

18

:

ColorTranslator.FromHtml("#003399") 

Diğer Yolları:

Public Function ConvertToRbg(ByVal HexColor As String) As Color 
    Dim Red As String 
    Dim Green As String 
    Dim Blue As String 
    HexColor = Replace(HexColor, "#", "") 
    Red = Val("&H" & Mid(HexColor, 1, 2)) 
    Green = Val("&H" & Mid(HexColor, 3, 2)) 
    Blue = Val("&H" & Mid(HexColor, 5, 2)) 
    Return Color.FromArgb(Red, Green, Blue) 
End Function 

ya:

Public Shared Function HexToColor(ByVal hexColor As String) As Color 
    If hexColor.IndexOf("#"c) <> -1 Then 
     hexColor = hexColor.Replace("#", "") 
    End If 
    Dim red As Integer = 0 
    Dim green As Integer = 0 
    Dim blue As Integer = 0 
    If hexColor.Length = 6 Then 
     red = Integer.Parse(hexColor.Substring(0, 2), NumberStyles.AllowHexSpecifier) 
     green = Integer.Parse(hexColor.Substring(2, 2), NumberStyles.AllowHexSpecifier) 
     blue = Integer.Parse(hexColor.Substring(4, 2), NumberStyles.AllowHexSpecifier) 
    ElseIf hexColor.Length = 3 Then 
     red = Integer.Parse(hexColor(0).ToString() + hexColor(0).ToString(), NumberStyles.AllowHexSpecifier) 
     green = Integer.Parse(hexColor(1).ToString() + hexColor(1).ToString(), NumberStyles.AllowHexSpecifier) 
     blue = Integer.Parse(hexColor(2).ToString() + hexColor(2).ToString(), NumberStyles.AllowHexSpecifier) 
    End If 
    Return Color.FromArgb(red, green, blue) 
End Function 

ya:

Dim c As String = "#ffffff" 
    c = Replace(c, "#", "") 
    c = "&H" & c 
    ColorTranslator.FromOle(c) 

veya:

Public Function hexToRbgNew(ByVal Hex As String) As Color 
    Hex = Replace(Hex, "#", "") 
    Dim red As String = "&H" & Hex.Substring(0, 2) 
    Hex = Replace(Hex, red, "", , 1) 
    Dim green As String = "&H" & Hex.Substring(0, 2) 
    Hex = Replace(Hex, green, "", , 1) 
    Dim blue As String = "&H" & Hex.Substring(0, 2) 
    Hex = Replace(Hex, blue, "", , 1) 
    Return Color.FromArgb(red, green, blue) 
End Function 
+0

Hızlısınız, teşekkürler !. – Nh123

+0

Sorun Yok. :-) – famf

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