İşaretlenmemiş onay kutularını işaretlendiğinde, işaretlenmemiş tüm onay kutularını devre dışı bırakmaya çalışıyorum.Jquery onay kutularını işaretlemeyi ve devre dışı bırakma onay kutularını işaretleme
Kodum işte burada çalışmıyor: http://jsfiddle.net/mtYtW/18/
Benim jQuery:
var countchecked = $('table input[type="checkbox"]').find(":checked").length
if(countcheckhed > 5) {
$("table input:checkbox").attr("disabled", true);
} else {}
Benim HTML:
<table cellspacing="0" cellpadding="0" width="770px;">
<tbody><tr style="border: 1px solid green; height: 40px; font-size: 14px;">
<th>Feature 1</th>
<th>Feature 2</th>
<th>Feuture 3</th>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
<tr>
<td class="checkit"><input type="hidden" value="0" name="search[windows_is_true]"><input type="checkbox" value="1" name="search[windows_is_true]" id="search_windows_is_true"></td>
<td>Test 1</td>
<td>Test 2</td>
<td>Test 3</td>
<td>Test 4</td>
<td>Test 5</td>
<td>Test 6</td>
</tr>
</tbody></table>
yanı soruya kodunuzu ekleyin. Gelecekte jsfiddle hiç kaybolursa soru hala geçerli olacaktır. –
Sağladığınız js, sadece kodun yüklenmesinden geçer ve tekrar kontrol etmez. Tüm onay kutularını alıp bir .click özelliği eklemeye ve kontrol sayısını yeniden değerlendirmeye çalışın. –
countcheckhed yanlış yazılmış. – Narnian