tek bir tabloda iki sorgunun sonuçlarını gösterme

Question

Seçtiğim sorgular, kaldırdığım t0.brandID = null değil, yalnızca bir tablodaki sorgunun sonucunu almanız gerekir.

brandid brandname cdt    udt brandstatus addedby branid_average brandid_min brandid_max branid_count 
    8 budwieser 2013-11-14  2014-02-12 1 8   46    8    92    7 
    18 budwieser 2013-11-15  2013-11-15 1 1   null   null   null   null 
    ........................................................  null   null   null   null 
    --------------------------------------------------------  null   null   null   null 

:

brandid brandname  cdt      udt  brandstatus added by 

    8 budwieser 2013-11-14 16:26:43.913 2014-02-12 19:26:43.913 1 8 
    18 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    23 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    37 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    63 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    82 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    92 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 

ve

brandid_average brandid_min brandid_max brandid_count 
46    8    92    7 

Ben aşağıda sonucu göstermek istiyorum:

SELECT 
    t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy 
FROM 
    brands t0 
WHERE 
    t0.brandName = 'budwieser' 

SELECT 
    AVG(CAST (brandID AS bigint)) AS brandID_AVERAGE, 
    MIN(CAST (brandID AS bigint)) as branid_min, 
    MAX(CAST (brandID AS bigint)) as brandid_max, 
    COUNT(CAST (brandID AS bigint)) as brandid_count 
FROM 
    (SELECT 
     t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy 
    FROM 
     brands t0 
    WHERE 
     t0.brandID = null OR t0.brandName = 'budwieser') temptable 

yukarıdaki sorgunun sonucu resmin altındaki gibi iki farklı tablolarda olduğu

Answer 1

İki tabloda bu senaryoda sonuçların birleştirilmesi gerekir, hem tablolardan seçim yaparak basit yapılabilir. , örneğin tablo1, tablo2.

Table1 has columns id,name,age 
table2 has columns someid,group,gender 

aşağıda biçimini göstermek için sonuç için

basit sorgu geçerli: Benzer yukarıdaki soru için

select t1.*,t2.* from table1 t1,table2 t2 

id name age someid group gender 
1 one 1 10  5  M 

biz bir tablo beyan ve değerleri kaydetmek zorunda var hiçbir fiziksel tablo olmadığı için geçici tablo ve sonra sadece soru olarak istediğiniz sonucu döndürecek tabloları seçin.

 drop table #mytemptable --- droping the temporary table if exists 
//select query 
     select AVG(CAST (brandID AS bigint)) AS brandID_AVERAGE, 
     min(CAST (brandID AS bigint)) as branid_min, 
     MAX(CAST (brandID AS bigint)) as brandid_max, 
     COUNT(CAST (brandID AS bigint)) as brandid_count 
into #mytemptable ---//Here inserting the selected values from below query to temporary table 
    from 
     (SELECT t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy 

     FROM brands t0 
     Where t0. brandID=null OR t0. brandName='budwieser' 

     ) temptable 
     //simple select from both tables 
     SELECT t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy ,t2.* 
     from brands t0,#mytemptable t2 
     where t0.brandName='budwieser' 

beklenen sonuç olacaktır:

Düzenli eşitlik operatörünü kullanarak NULL` `kontrol edemez

brandID brandName cdt udt brandstatus AddedBy brandID_AVERAGE branid_min brandid_max brandid_count 
8 budwieser 2013-11-14 16:26:43.913 2014-02-12 19:26:43.913 1 8 46 8 92 7 
18 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
23 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
37 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
63 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
82 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
92 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 

Answer 2

SELECT t0.brandID, 
     t0.brandName, 
     t0.cdt, 
     t0.udt, 
     t0.brandstatus, 
     t0.AddedBy, 
     AVG(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS brandID_AVERAGE, 
     MIN(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS branid_min, 
     MAX(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS brandid_max, 
     COUNT(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS brandid_count 
FROM brands t0 
WHERE t0.brandName = 'budwieser'