Bu eski bir yazıdır, ancak "bahar güvenliği ajax girişi" için en iyi sonuçlardan biri olarak ortaya çıkmaktadır, bu yüzden çözümümü paylaşacağımı düşündüm. Spring Security standartlarını izler ve kurulumu oldukça kolaydır, hile güvenlik yapılandırmanızda 2 <http> öğeye sahip olmak, REST/Ajax için bir ve uygulamanın geri kalanı için bir tane (normal HTML sayfaları). <http> 'un göründüğü sıra önemlidir, daha spesifik olandan daha jenerik URL'lere gitmek zorundadır, <http>'un içindeki <url-intercept> öğeleri gibi.
Adım 1: Kurulum iki ayrı <http> sitesindeki
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<!-- a shared request cache is required for multiple http elements -->
<beans:bean id="requestCache" class="org.springframework.security.web.savedrequest.HttpSessionRequestCache" />
<!-- remove security from static resources to avoid going through the security filter chain -->
<http pattern="/resources/**" security="none" />
<!-- http config for REST services (AJAX interface)
=================================================== -->
<http auto-config="true" use-expressions="true" pattern="/rest/**">
<!-- login configuration
login-processing-url="/rest/security/login-processing" front-end AJAX requests for authentication POST to this URL
login-page="/rest/security/login-page" means "authentication is required"
authentication-failure-url="/rest/security/authentication-failure" means "authentication failed, bad credentials or other security exception"
default-target-url="/rest/security/default-target" front-end AJAX requests are redirected here after success authentication
-->
<form-login
login-processing-url="/rest/security/login-processing"
login-page="/rest/security/login-page"
authentication-failure-url="/rest/security/authentication-failure"
default-target-url="/rest/security/default-target"
always-use-default-target="true" />
<logout logout-url="/rest/security/logout-url" />
<!-- REST services can be secured here, will respond with JSON instead of HTML -->
<intercept-url pattern="/rest/calendar/**" access="hasRole('ROLE_USER')" />
<!-- other REST intercept-urls go here -->
<!-- end it with a catch all -->
<intercept-url pattern="/rest/**" access="isAuthenticated()" />
<!-- reference to the shared request cache -->
<request-cache ref="requestCache"/>
</http>
<!-- http config for regular HTML pages
=================================================== -->
<http auto-config="true" use-expressions="true">
<form-login
login-processing-url="/security/j_spring_security_check"
login-page="/login"
authentication-failure-url="/login?login_error=t" />
<logout logout-url="/security/j_spring_security_logout" />
<intercept-url pattern="/calendar/**" access="hasRole('ROLE_USER')" />
<!-- other intercept-urls go here -->
<!-- in my app's case, the HTML config ends with permitting all users and requiring HTTPS
it is always a good idea to send sensitive information like passwords over HTTPS -->
<intercept-url pattern="/**" access="permitAll" requires-channel="https" />
<!-- reference to the shared request cache -->
<request-cache ref="requestCache"/>
</http>
<!-- authentication manager and other configuration go below -->
</beans:beans>
Adım 2: İstirahat Doğrulama Kontrol
import org.springframework.http.HttpHeaders;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.security.core.Authentication;
import org.springframework.security.core.context.SecurityContextHolder;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import flexjson.JSONSerializer;
@Controller
@RequestMapping(value = "/rest/security")
public class RestAuthenticationController {
public HttpHeaders getJsonHeaders() {
HttpHeaders headers = new HttpHeaders();
headers.add("Content-Type", "application/json");
return headers;
}
@RequestMapping(value="/login-page", method = RequestMethod.GET)
public ResponseEntity<String> apiLoginPage() {
return new ResponseEntity<String>(getJsonHeaders(), HttpStatus.UNAUTHORIZED);
}
@RequestMapping(value="/authentication-failure", method = RequestMethod.GET)
public ResponseEntity<String> apiAuthenticationFailure() {
// return HttpStatus.OK to let your front-end know the request completed (no 401, it will cause you to go back to login again, loops, not good)
// include some message code to indicate unsuccessful login
return new ResponseEntity<String>("{\"success\" : false, \"message\" : \"authentication-failure\"}", getJsonHeaders(), HttpStatus.OK);
}
@RequestMapping(value="/default-target", method = RequestMethod.GET)
public ResponseEntity<String> apiDefaultTarget() {
Authentication authentication = SecurityContextHolder.getContext().getAuthentication();
// exclude/include whatever fields you need
String userJson = new JSONSerializer().exclude("*.class", "*.password").serialize(authentication);
return new ResponseEntity<String>(userJson, getJsonHeaders(), HttpStatus.OK);
}
}
Adım 3: AJAX formu gönder ve tepki işlem, gerekli jQuery adlı kullanıcının ajaxForm kütüphanesi
<form action="/rest/security/login-processing" method="POST">
...
</form>
$('form').ajaxForm({
success: function(response, statusText, xhr, $form) {
console.log(response);
if(response == null || response.username == null) {
alert("authentication failure");
} else {
// response is JSON version of the Spring's Authentication
alert("authentication success");
}
},
error: function(response, statusText, error, $form) {
if(response != null && response.message == "authentication-failure") {
alert("authentication failure");
}
}
});
Çözümünüz güzel görünüyor ama burada 'için/dinlenme/güvenlik/giriş-işleme" tanımlı –
@MichaelDeKeyser yanıt kontrolör yöntemidir? - o SpringSecurity tarafından sağlanan UsernamePasswordAuthenticationFilter eşlenmiş, dokümanlar ve arama bakmak 'UsernamePasswordAuthenticationFilter' ve 'login-processing-url' için. http://docs.spring.io/autorepo/docs/spring-security/3.2.0.RELEASE/reference/htmlsingle/ – SergeyB
SpringConfig of Spring ile bunu denedim Güvenlik, nihayet pes etmek ve XML ftw! – Boon