EDIT
Aşağıdaki kod! Tekrar teşekkürler andyk! Orijinal soru için aşağıya bakınız.JavaScript nesnesi ciltleme
HTML
<!-- feature -->
<div class="feature col-md-8">
<div class="feature-slides">
<div class="feature-slide active" style="background-image: url('/images/1.jpg');"></div>
<div class="feature-slide" style="background-image: url('/images/2.jpg');"></div>
</div>
<ul class="row feature-pagination">
<li data-slide-index="0" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/1.jpg');"></button>
</li>
<li data-slide-index="1" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/2.jpg');"></button>
</li>
</ul>
</div>
<!-- feature -->
<div class="feature col-md-8">
<div class="feature-slides">
<div class="feature-slide active" style="background-image: url('/images/1.jpg');"></div>
<div class="feature-slide" style="background-image: url('/images/2.jpg');"></div>
</div>
<ul class="row feature-pagination">
<li data-slide-index="0" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/1.jpg');"></button>
</li>
<li data-slide-index="1" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/2.jpg');"></button>
</li>
</ul>
</div>
JavaScript
<script>
// feature class + constructor
var Feature = function(element) {
//THIS WAS THE PROBLEM, NEEDED A VAR
var _this = this;
//collect elements as jqueries
_this.element = $(element);
_this.slides = $(_this.element).find('.feature-slide');
_this.pagination = $(_this.element).find('.feature-pagination > li');
//setup onclicks for pagination
$(_this.pagination).click(function() {
_slide = this;
var slideIndexToDisplay = $(_slide).attr("data-slide-index");
$(_this.slides).removeClass('active');
$(_this.slides).eq(slideIndexToDisplay).addClass('active');
});
};
$(document).ready(function() {
// init feature widget
var features = $('.feature');
$.each(features, function(){
_this = this;
_feature = new Feature(_this);
});
});
</script>
ORİJİNAL SORU
Bunu milyonlarca kez önce yaptığım gibi hissediyorum gibi bu, oldukça saçma ama Burada ne yapıyorum emin değilim. Her bir özelliğin kendini etkilemesini istiyorum, ancak ikinci özellik nesnesi, ilk önce değil, ikincideki slaytları değiştirir, böylece nesnelerim birbirine karışıyor.
HTML
<!-- feature -->
<div class="feature col-md-8">
<div class="feature-slides">
<div class="feature-slide active" style="background-image: url('/images/1.jpg');"></div>
<div class="feature-slide" style="background-image: url('/images/2.jpg');"></div>
</div>
<ul class="row feature-pagination">
<li data-slide-index="0" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/1.jpg');"></button>
</li>
<li data-slide-index="1" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/2.jpg');"></button>
</li>
</ul>
</div>
<!-- feature -->
<div class="feature col-md-8">
<div class="feature-slides">
<div class="feature-slide active" style="background-image: url('/images/1.jpg');"></div>
<div class="feature-slide" style="background-image: url('/images/2.jpg');"></div>
</div>
<ul class="row feature-pagination">
<li data-slide-index="0" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/1.jpg');"></button>
</li>
<li data-slide-index="1" class="col-xs-4 col-sm-3 col-md-2">
<button style="background-image: url('/images/2.jpg');"></button>
</li>
</ul>
</div>
JavaScript
$(document).ready(function() {
// init feature widget
$('.feature').each(function(){
_this = this;
feature = new Feature(_this);
// feature.init();
});
});
// feature class + constructor
var Feature = function (element) {
//save this!
_this = this;
//collect elements as jqueries
_this.element = $(element);
_this.slides = $(_this.element).find('.feature-slide');
_this.pagination = $(_this.element).find('.feature-pagination > li');
//setup onclicks for pagination
$(_this.pagination).click(function() {
_slide = this;
slideIndexToDisplay = $(_slide).attr("data-slide-index");
$(_this.slides).removeClass('active');
$(_this.slides).eq(slideIndexToDisplay).addClass('active');
});
};
Bu HTML'nin işlenmiş bir örneğini (CSS dahil) görmeden yardımcı olacağımızdan kuşkuluyum. – jfriend00