Question

'2015_11_01_00_00' dizesi var. Aşağıdaki kodu denedim, ancak değeri bulunamadı.

#!/bin/bash 

echo "mohit" 

date_var="2015_11_01_00_00" 

echo $date_var 

arr=$(echo $date_var | tr "_" "\n") 

IFS='_ ' read -r -a arr <<< "$date_var" 
#echo $arr 
echo ${arr[0]} 
echo ${arr[1]} 
echo ${arr[2]} 
echo ${arr[3]} 
echo ${arr[4]} 

updated_date="${arr[0]}"-"${arr[1]}"-"${arr[2]}"-"${arr[3]}"-"${arr[4]}" 
echo $updated_date 

TMRW_DATE=`date --date="$updated_date" +"%s"` 
echo "$TMRW_DATE" 

Answer 1

Bu seferki hile yapmak gerekir: Burada

#!/bin/bash 

echo "mohit" 

date_var="2015_11_01_00_00" 

updated_date=`echo ${date_var} | sed -e 's,_,/,;s,_,/,;s,_, ,;s/_/:/'` 
echo ${updated_date} 

TMRW_DATE=`date -d "$updated_date" +"%s"` 
echo "$TMRW_DATE" 

Answer 2

GNU date syntax kullanarak, bunu yapmak için tek yoldur:

#!/bin/bash 
echo "mohit" 
date_var="2015_11_01_00_00" 

TMRW_DATE=$(
    set -- $(echo $date_var | tr "_" " ") 
    date --date="$1-$2-$3 $4:$5" +"%s" 
) 

echo "$TMRW_DATE" 

ve bu OS X date implementation ile çalışmalıdır:

#!/bin/bash 
echo "mohit" 

date_var="2015_11_01_00_00" 
TMRW_DATE=$(date -j -f "%Y_%m_%d_%H_%M" "$date_var" +%s) 

echo "$TMRW_DATE"