python: herhangi bir sayı girin ve metne dönüştürün

Question

Ondalık ve çıktı metni dahil olmak üzere herhangi bir sayıyı girmek için bu programı genişletmek üzere. yani) 45.23 Kırk beş nokta yirmiüç

num1 = str(input("enter a dollar amt:")) 

numToString = {'1.00':'one dollar', '1.50':'one dollar and fifty cents',\ 
'2.00':'two dollars', '3.00': 'three dollars', '4.00':'four dollars', \ 
'5.00':'five dollars', '6.00':'six dollars', '7.00':'seven dollars', \ 
'8.00':'eight dollars', '9.00':'nine dollars'} ; 

for char in num1: 
    print(numToString[char]) 

Answer 1

Deneyin:

import math 

# Tokens from 1000 and up 
_PRONOUNCE = [ 
    'vigintillion', 
    'novemdecillion', 
    'octodecillion', 
    'septendecillion', 
    'sexdecillion', 
    'quindecillion', 
    'quattuordecillion', 
    'tredecillion', 
    'duodecillion', 
    'undecillion', 
    'decillion', 
    'nonillion', 
    'octillion', 
    'septillion', 
    'sextillion', 
    'quintillion', 
    'quadrillion', 
    'trillion', 
    'billion', 
    'million', 
    'thousand', 
    '' 
] 

# Tokens up to 90 
_SMALL = { 
    '0' : '', 
    '1' : 'one', 
    '2' : 'two', 
    '3' : 'three', 
    '4' : 'four', 
    '5' : 'five', 
    '6' : 'six', 
    '7' : 'seven', 
    '8' : 'eight', 
    '9' : 'nine', 
    '10' : 'ten', 
    '11' : 'eleven', 
    '12' : 'twelve', 
    '13' : 'thirteen', 
    '14' : 'fourteen', 
    '15' : 'fifteen', 
    '16' : 'sixteen', 
    '17' : 'seventeen', 
    '18' : 'eighteen', 
    '19' : 'nineteen', 
    '20' : 'twenty', 
    '30' : 'thirty', 
    '40' : 'forty', 
    '50' : 'fifty', 
    '60' : 'sixty', 
    '70' : 'seventy', 
    '80' : 'eighty', 
    '90' : 'ninety' 
} 

def get_num(num): 
    '''Get token <= 90, return '' if not matched''' 
    return _SMALL.get(num, '') 

def triplets(l): 
    '''Split list to triplets. Pad last one with '' if needed''' 
    res = [] 
    for i in range(int(math.ceil(len(l)/3.0))): 
     sect = l[i * 3 : (i + 1) * 3] 
     if len(sect) < 3: # Pad last section 
      sect += [''] * (3 - len(sect)) 
     res.append(sect) 
    return res 

def norm_num(num): 
    """Normelize number (remove 0's prefix). Return number and string""" 
    n = int(num) 
    return n, str(n) 

def small2eng(num): 
    '''English representation of a number <= 999''' 
    n, num = norm_num(num) 
    hundred = '' 
    ten = '' 
    if len(num) == 3: # Got hundreds 
     hundred = get_num(num[0]) + ' hundred' 
     num = num[1:] 
     n, num = norm_num(num) 
    if (n > 20) and (n != (n/10 * 10)): # Got ones 
     tens = get_num(num[0] + '0') 
     ones = get_num(num[1]) 
     ten = tens + ' ' + ones 
    else: 
     ten = get_num(num) 
    if hundred and ten: 
     return hundred + ' ' + ten 
     #return hundred + ' and ' + ten 
    else: # One of the below is empty 
     return hundred + ten 

def num2eng(num): 
    '''English representation of a number''' 
    num = str(long(num)) # Convert to string, throw if bad number 
    if (len(num)/3 >= len(_PRONOUNCE)): # Sanity check 
     raise ValueError('Number too big') 

    if num == '0': # Zero is a special case 
     return 'zero ' 

    # Create reversed list 
    x = list(num) 
    x.reverse() 
    pron = [] # Result accumolator 
    ct = len(_PRONOUNCE) - 1 # Current index 
    for a, b, c in triplets(x): # Work on triplets 
     p = small2eng(c + b + a) 
     if p: 
      pron.append(p + ' ' + _PRONOUNCE[ct]) 
     ct -= 1 
    # Create result 
    pron.reverse() 
    return ', '.join(pron) 

if __name__ == '__main__': 

    numbers = [1.37, 0.07, 123456.00, 987654.33] 
    for number in numbers: 
     dollars, cents = [int(num) for num in str(number).split(".")] 

     dollars = num2eng(dollars) 
     if dollars.strip() == "one": 
      dollars = dollars + "dollar and " 
     else: 
      dollars = dollars + "dollars and " 

     cents = num2eng(cents) + "cents" 
     print dollars + cents