Çoklu Tarih Alanlarını Gruplandıran SQL Sorgusu

Question

Birkaç tarih alanına sahip bir tablom var. Örneğin, kusur tablosunda aşağıdakilere sahibim: dateAssigned, dateCompleted, dateResolved. Ben gibi kusurları özetleyen bir sorgu almaya çalışıyorum:

  | Number Assigned | Number Completed | Number Resolved 
-----------------------------+------------------+----------------- 
    Mar-2011 |  33   |  22  |  33   
    Apr-2011 |  10   |  11  |  22 
    May-2011 |  22   |  66  |  46 

vb ben boşuna aşağıdaki ile geldi

: özetleme için doğru

SELECT year(d.dateAssigned) 
     ,month(d.dateAssigned) 
     ,COUNT(d.dateAssigned) 
     ,COUNT(d.dateCompleted) 
     ,COUNT(d.dateResolved) 
    FROM defect d 
    GROUP BY year(d.dateAssigned), month(d.dateAssigned) 
    ORDER BY year(d.dateAssigned), month(d.dateAssigned) 

Bu işleri dateAssigned kusurları, ancak diğerleri için değil. Bunun büyük olasılıkla, tarihine göre gruplandırdığımdan kaynaklandığının farkındayım, ama bunu nasıl yapacağımı bilmiyorum.

Herhangi bir yardım için teşekkür ederiz.

Answer 1

Bunu yapmanın bir yolu budur.

SELECT YEAR(typedate), 
     MONTH(typedate), 
     SUM(CASE 
      WHEN TYPE = 'assinged' THEN 1 
      ELSE 0 
      END) number_assigned, 
     SUM(CASE 
      WHEN TYPE = 'completed' THEN 1 
      ELSE 0 
      END) number_completed, 
     SUM(CASE 
      WHEN TYPE = 'Resolved' THEN 1 
      ELSE 0 
      END) number_resolved 
FROM (SELECT dateassigned typedate, 
       'assinged' AS TYPE 
     FROM sampledata 
     WHERE dateassigned IS NOT NULL 
     UNION ALL 
     SELECT datecompleted typedate, 
       'completed' AS TYPE 
     FROM sampledata 
     WHERE datecompleted IS NOT NULL 
     UNION ALL 
     SELECT dateresolved typedate, 
       'Resolved' AS TYPE 
     FROM sampledata 
     WHERE dateresolved IS NOT NULL) data 
GROUP BY YEAR(typedate), 
      MONTH(typedate) 
ORDER BY YEAR(typedate), 
      MONTH(typedate) 

seçme alt iki sütun typedate ve verileri özetlemeyi SUM(CASE... kullanılan Sonra bu

typedate type 
-------- --------- 
1/1/2011 assinged 
1/1/2011 assinged 
1/1/2011 assinged 
2/1/2011 completed 
2/1/2011 completed 
2/3/2011 Resolved 

gibi görünecek

yazın oluşturur. Bunu destekleyen bir RDBMS kullanıyorsanız, ben yıl ve aya

biçimlendirmesini yapmak size bırakacağım pivot yerine

son çıkış bu

     Number_Assigned Number_completed Number_Resolved 
----------- ----------- --------------- ---------------- --------------- 
2011  1   3    0    0 
2011  2   0    2    1 

gibi görünür kullanabilirsiniz

Answer 2

Başka bir yol, tablolarda months alanları ile: year, month, firstDate, nextMonthFirstDate, ya sinek şeklinde veya geçici tablo olarak veya kalıcı tablo olarak (100 yıl ve 100x12 satırlarla depolanmış bir tabloya sahip olmak çok fazla yer kaplamaz ve diğer sorgular için kullanışlı) ve bunun gibi bir şey kullanın ('e eşdeğerdir) i zarif bir yol göremiyorum

SELECT 
    (SELECT COUNT(*) 
     FROM defect AS d 
     WHERE m.firstDate <= d.dateAssigned 
     AND d.dateAssigned < m.nextMonthFirstDate 
    ) AS Number_Assigned 
    . (SELECT COUNT(*) 
     FROM defect AS d 
     WHERE m.firstDate <= d.dateCompleted 
     AND d.dateCompleted < m.nextMonthFirstDate 
    ) AS Number_Completed 
    . (SELECT COUNT(*) 
     FROM defect AS d 
     WHERE m.firstDate <= d.dateResolved 
     AND d.dateResolved < m.nextMonthFirstDate 
    ) AS Number_Resolved 
FROM months AS m 
ORDER BY m.year 
     , m.month 

Answer 3

SELECT year(defectDate), month(defectDate), SUM(assigned), SUM(resolved), SUM(completed) 
    FROM (
    SELECT d.dateAssigned AS defectDate, 1 AS assigned, 0 AS resolved, 0 AS completed 
     FROM defect d 
    UNION ALL 
    SELECT d.dateCompleted AS defectDate, 0 AS assigned, 1 AS resolved, 0 AS completed 
     FROM defect d 
    UNION ALL 
    SELECT d.dateResolved AS defectDate, 0 AS assigned, 0 AS resolved, 1 AS completed 
     FROM defect d 
) 
    GROUP BY year(defectDate), month(defectDate) 
    ORDER BY year(defectDate), month(defectDate) 

Answer 4

SELECT year(d.dateAssigned) 
     ,month(d.dateAssigned) 
     ,COUNT(d.dateAssigned) 
     ,(SELECT count(*) 
     FROM defect as dc 
     WHERE month(dc.dateCompleted) = month(d.dateAssigned) and 
       year(dc.dateCompleted) = year(d.dateAssigned)) 
     ,(SELECT count(*) 
     FROM defect as dr 
     WHERE month(dr.dateResolved) = month(d.dateAssigned) and 
       year(dr.dateResolved) = year(d.dateAssigned)) 
FROM defect d 
GROUP BY year(d.dateAssigned), month(d.dateAssigned) 

Answer 5

biz durumda tarafından grup kullanırsanız bu mümkündür

SELECT CASE 
     WHEN (year(Challan_Date) is null or year(TAX_INVOICE_Date)!=null) THEN year(TAX_INVOICE_Date) 
     WHEN (year(Challan_Date) != null or year(TAX_INVOICE_Date) is null) THEN YEAR(Challan_Date) 
     WHEN (year(Challan_Date) is null or year(TAX_INVOICE_Date)is null) THEN 'NA' 
     WHEN (year(Challan_Date) != null or year(TAX_INVOICE_Date)!= null) THEN year(Challan_Date) 
     ELSE year(TAX_INVOICE_Date) END as Dates_Record, TAX_INVOICE_Date, Challan_Date 
FROM TransactionRecords