Python

Question

'da zaman ayarlı çalışma yaparken, sözlükten birden fazla anahtarı değiştirin Anahtarların tamsayı olduğu bir sözlüğe sahibim. Anahtarlardan birini bir tarihte keyfi olarak değiştirdim ve diğer anahtarları değiştirmem gerekiyor.

Örnek veri:

{'C-STD-B&M-SUM': {datetime.date(2015, 7, 12): 0, 
       -1: 0.21484699999999998, 
       -2: 0.245074, 
       -3: 0.27874} 

Beklenen çıkış: Bugüne kadar

{'C-STD-B&M-SUM': {datetime.date(2015, 7, 12): 0, 
       datetime.date(2015, 7, 11): 0.21484699999999998, 
       datetime.date(2015, 7, 10): 0.245074, 
       datetime.date(2015, 7, 9): 0.27874} 

Güncel kodu: Sen gibi bir şey deneyebilirsiniz

def change_start_date(dictionary_with_temporal_distribution): 
    unsw_mid_year_end_date = datetime.date(2015, 7, 12) 
    dictionary_with_temporal_distribution['C-STD-B&M-SUM'][unsw_mid_year_end_date] = dictionary_with_temporal_distribution['C-STD-B&M-SUM'][0] 
    del dictionary_with_temporal_distribution['C-STD-B&M-SUM'][0] 
    for k, v in dictionary_with_temporal_distribution['C-STD-B&M-SUM'].items(): 

Answer 1

-

def change_start_date(dictionary_with_temporal_distribution): 
    unsw_mid_year_end_date = datetime.date(2015, 7, 12) 
    for k in list(dictionary_with_temporal_distribution['C-STD-B&M-SUM'].keys()): 
     dictionary_with_temporal_distribution['C-STD-B&M-SUM'][unsw_mid_year_end_date + timedelta(days=k)] = dictionary_with_temporal_distribution['C-STD-B&M-SUM'][k] 
     del dictionary_with_temporal_distribution['C-STD-B&M-SUM'][k] 

Answer 2

Sen dict anlama sözdizimini kullanın ve dönüşümü ve tuşları değiştirebilirsiniz:

dct = {datetime.date(2015, 7, 12): 0, 
    -1: 0.21484699999999998, 
    -2: 0.245074, 
    -3: 0.27874} 

def offset(offset, base): 
    """Applies an offset in days to a base date. 
     If the offset is already a date it is returned as is.""" 
    if type(offset) == datetime.date: 
     return offset 
    return base + datetime.timedelta(offset) 

def offset_keys(dct, base): 
    """Takes a dict and runs offset(key, base) on all keys""" 
    return { offset(k, base): v for k, v in dct.items() } 

pprint(offset_keys(dct, datetime.date(2015, 7, 12))) 

{datetime.date(2015, 7, 9): 0.27874, 
datetime.date(2015, 7, 10): 0.245074, 
datetime.date(2015, 7, 11): 0.21484699999999998, 
datetime.date(2015, 7, 12): 0}