Spark Combinebykey JAVA lambda ifadesi

Question

Bir (JavaPairRDD<Integer, Double> pairs) anahtarıyla ortalamayı hesaplamak için lambda işlevini kullanmak istiyorum. Ancak

java.util.function.Function<Double, Tuple2<Double, Integer>> createAcc = x -> new Tuple2<Double, Integer>(x, 1); 

BiFunction<Tuple2<Double, Integer>, Double, Tuple2<Double, Integer>> addAndCount = (Tuple2<Double, Integer> x, Double y) -> { return new Tuple2(x._1()+y, x._2()+1); }; 

BiFunction<Tuple2<Double, Integer>, Tuple2<Double, Integer>, Tuple2<Double, Integer>> combine = (Tuple2<Double, Integer> x, Tuple2<Double, Integer> y) -> { return new Tuple2(x._1()+y._1(), x._2()+y._2()); }; 

JavaPairRDD<Integer, Tuple2<Double, Integer>> avgCounts = pairs.combineByKey(createAcc, addAndCount, combine); 

diplays bu hata Tutulma: O nedenle ben aşağıdaki kodu geliştirdi

The method combineByKey(Function<Double,C>, Function2<C,Double,C>, Function2<C,C,C>) in the type JavaPairRDD<Integer,Double> is not applicable for the arguments (Function<Double,Tuple2<Double,Integer>>, 
BiFunction<Tuple2<Double,Integer>,Double,Tuple2<Double,Integer>>, BiFunction<Tuple2<Double,Integer>,Tuple2<Double,Integer>,Tuple2<Double,Integer>>) 

Answer 1

combineByKey yöntemi org.apache.spark.api.java.function.Function2 yerine java.util.function.BiFunction bekliyor. Yani ya sen geç

java.util.function.Function<Double, Tuple2<Double, Integer>> createAcc = 
    x -> new Tuple2<Double, Integer>(x, 1); 

Function2<Tuple2<Double, Integer>, Double, Tuple2<Double, Integer>> addAndCount = 
    (Tuple2<Double, Integer> x, Double y) -> { return new Tuple2(x._1()+y, x._2()+1); }; 

Function2<Tuple2<Double, Integer>, Tuple2<Double, Integer>, Tuple2<Double, Integer>> combine = 
    (Tuple2<Double, Integer> x, Tuple2<Double, Integer> y) -> { return new Tuple2(x._1()+y._1(), x._2()+y._2()); }; 

JavaPairRDD<Integer, Tuple2<Double, Integer>> avgCounts = 
    pairs.combineByKey(createAcc, addAndCount, combine);