django model yabancı anahtar queryset ilgili alanları seç

Question

Aşağıda gösterildiği gibi DJango'daki ilgili iki tablodan birleşimden seçim yapmaya çalışıyorum. Ancak diğer tablonun name alanını alamıyorum.

SQL biz yazabiliriz:

select person.phonenumber,membership.* from membership where person=name ; 

Bu phonenumber birlikte tüm membership alanları görüntüler, ancak Django hatayı atar:

Cannot resolve keyword 'phonenumber' into field

Hatta select_related ama hiçbir kullanımı ile çalıştık . Yanlış bir şey yapıyorum?

model.py:

from django.db import models 

# Create your models here. 
class Person(models.Model): 
    name = models.CharField(primary_key=True,max_length=128) 
    phonenumber = models.CharField(max_length=128) 
    city = models.CharField(max_length=128) 


    def __unicode__(self): 
     return self.name 

class Membership(models.Model): 
    person = models.ForeignKey(Person) 
    date_joined = models.DateField() 
    invite_reason = models.CharField(max_length=64) 


>>> print m.query 
SELECT `myapp_membership`.`id`, `myapp_membership`.`person_id`, `myapp_membership`.`date_joined`, `myapp_membership`.`invite_reason` FROM `myapp_membership` WHERE `myapp_membership`.`person_id` = x 
>>> m=Membership.objects.filter(person__name='x').select_related() 
>>> print m.query 
SELECT `myapp_membership`.`id`, `myapp_membership`.`person_id`, `myapp_membership`.`date_joined`, `myapp_membership`.`invite_reason`, `myapp_person`.`name`, `myapp_person`.`phonenumber`, `myapp_person`.`city` FROM `myapp_membership` INNER JOIN `myapp_person` ON (`myapp_membership`.`person_id` = `myapp_person`.`name`) WHERE `myapp_membership`.`person_id` = x 
>>> m=Membership.objects.filter(person__name='x').values('person','phonenumber').select_related() 
Traceback (most recent call last): 
    File "<console>", line 1, in <module> 
    File "/usr/local/lib/python2.6/dist-packages/Django-1.2.4-py2.6.egg/django/db/models/query.py", line 510, in values 
    return self._clone(klass=ValuesQuerySet, setup=True, _fields=fields) 
    File "/usr/local/lib/python2.6/dist-packages/Django-1.2.4-py2.6.egg/django/db/models/query.py", line 766, in _clone 
    c._setup_query() 
    File "/usr/local/lib/python2.6/dist-packages/Django-1.2.4-py2.6.egg/django/db/models/query.py", line 889, in _setup_query 
    self.query.add_fields(self.field_names, False) 
    File "/usr/local/lib/python2.6/dist-packages/Django-1.2.4-py2.6.egg/django/db/models/sql/query.py", line 1537, in add_fields 
    "Choices are: %s" % (name, ", ".join(names))) 
FieldError: Cannot resolve keyword 'phonenumber' into field. Choices are: date_joined, id, invite_reason, person 

Answer 1

phonenumberperson bir alandır, yani (şimdiye değerleri kullanmak değil Sorgu Kümesi istiyorsanız Ayrıca person__phonenumber

m=Membership.objects.filter(person__name='x').values('person','person__phonenumber'). 

Answer 2

içinde geçmesi gerekiyor) Bunu yapabilirsiniz:

m=Membership.objects.filter(person__name="x").select_related('person', depth=1) 

Maalesef bu tablodan sadece bir alanın nasıl alınacağını bilmiyorum ve hala bir queryset olsun.